avogadro says one mole of particles contain 6.02 x 10^23 particles. hence, 2 moles of water molecules contains 2 x 6.02 x 10^23 molecules.
one mole of particles contain 6.02 x 10^23 particles. consequently, 2 moles of water particles contain 2 x 6.02 x 10^23 atoms.
1. calculate the mass of each element
mass of c = 1.45 mg co₂ × (12.01 mg c/44.01 mg co₂) = 0.3957 mg c
mass of h = 0.89 mg h₂o × (2.016 mg h/18.02 mg h₂o) = 0.0996 mg h
mass of o = mass of compound - mass of c - mass of h = (1.55 – 0.3957 – 0.0996) mg = 1.055 mg
2. calculate the moles of each element
moles of c = 0.3957 mg c × 1mmol c/12.01 mg c = 0.03295 mol c
moles of h = 0.0996 mg h × 1 mmol h/1.008 mg h = 0.0988 mol h
moles of o = 1.055 mg o × 1 mmol o/ 16.00 mg o = 0.06592 mol o
3. calculate the molar ratios
divide all moles by the smallest number of moles.
c: 0.032 95/0.032 95 = 1
h: 0.0988/0.032 95 = 2.998
o: 0.065 92/0.032 95 = 2.001
4. round the ratios to the nearest integer
c: h: o = 1: 3: 2
5. write the empirical formula
the empirical formula is ch₃o.
answer: the gravitational pull on moon b is greater than on moon a because moon b is closer to the new planet than moon a.
the gravitational force exerted by the two objects on each other is inversely proportional to the square of the distance between the objects.
f = gravitational force or pull
g = gravitational constant on that planet
m = mass of the object-1
m = mass of object-2(mass of moon-a or moon-b)
r = distance between two objects
with decease in distance 'r' the force between the object increases or vice versa.so, from this we can say that the gravitational pull on moon-b is more than the gravitational pull on moon-a because the moon b is closer than the moon-a from the new planet.