Consider a square flat plate at zero incidence angle to a low-speed incompressible flow. the length of each side is 4 m. assume that the transition reynolds number is 5 × 105 and that the free-stream properties are those at standard sea level. calculate the friction drag on the flat plate when the free-stream velocity is
(a) 20 m/s and when it is
(b) 40 m/s.
(c) assuming that the friction drag, df, varies with velocity as , calculate the value of the exponent n based on the answers from (a) and (b). how close does n come to 2? that is, how close is the friction drag to obeying the velocity squared law?
answer with explanation:
when dealing with heavy loads, one needs to take certain precautions in order to avoid or prevent from injuries.
for instance, one should avoid lifting above the shoulder level which can end up pulling your muscle.
also, you can either break the load in parts if possible or get some for lifting heavy bulks.
moreover, one should try to lift with the legs while keeping the back straight and not twisting it.
answer & explanation:
"the force on a cutting tool are 2600n vertically downward" sounds a little unusual, since most of the time, the tool is above the object to be cut in such a way that the force acting "on the tool" is upwards. we will accept the statement as it is (downwards).
since the two forces are acting at right angles to each other, the resultant can be found using pythagoras theorem, namely
resultant = sqrt(2600^2+2100^2) = 3342 n (approx.)
the angle can be found using the arctangent function, or
angle = arctangent(2600/2100) = 51.07 degrees below the horizontal, since the 2600 n force is acting downwards.
d is the answer
by increasing magnification you decrease the field of view.
the answer is a.
hope this .