such a box has one vertex at the origin (0, 0, 0), and the vertex opposite this one is affixed to the plane with coordinates . the volume of the box is then , which we want to maximize subject to the constraint . of course, we don't want a degenerate box, so we assume each of is positive.
we can use lagrange multipliers - the lagrangian is
with partial derivatives (set equal to 0)
so the largest volume that can be attained is .
step-by-step explanation:plot the coordinates on the gridconnect the dotsmake triangles into a rectangle and find area of itarea of triangle is length times width divide by 2, so divide area of rectangle by 2multiply area by 3
(a+5) (a+5) - b²
a²+10a+25-b² = (a-5) (a-5) ..easy xd
-b² stays constant ..obviously xd
cost price of the baby blanket is $14.35 and markup is $15.64.
as we know selling price of the baby blanket is $29.99 and the markup percentage is 109%.we have to calculate the cost and markup of the blanket.
let the cost price c.p.= $x
then with the markup selling price s.p. will be = x+ 109% of x
s.p.= x+1.09x =2.09x
this s.p. is $29.99 given from the question.
2.09x = 29.99
x = 29.99/2.09 = 14.35
and markup = 1.09×14.35 = $15.64