Abox (with no top) is to be constructed from a piece of cardboard of sides a and b by cutting out squares of length h from the corners and folding up the sides. find the value of h that maximizes the volume of the box if
a = 7 and b = 12

answer:

hello : 5/8; 65/100   ; 2/3   ; 7/10

step-by-step explanation:

lcm:   (least common divisor) for : 3 ; 10 ; 8 ; 100 is   600

2/3 = (2×200)/(3×200) = 400 /600

7/10 = (7×60)/(10×60) = 420 /600

5/8 = (5×75)/(8×75) = 375 /600

65/100 = (65×6)/(100×6) = 390 /600

the order of these fractions from least to greatest   is:

5/8 ; 65/100   ; 2/3   ; 7/10

answer:

step-by-step explanation:

to answer these questions we must order the expenses and the rates according to their units.

so:

1. the consumption of the mall is:

17,4000 kilowatts/hour

the costs for this consumption are:

energy cost

$ 0.08 per kilowatt hour.

fuel adjustment cost

$ 0.017 per kilowatt hour.

then the cost for this consumption is:

17400 kw/h (0.08 $/(kw/h)) + 17400 kw/h(0.017 $/[kilowatt/hour])

the second consumption is:

2. maximum load

92 kilowatts.

the demand cost is:

  $ 5.95 per kilowatt

then the cost for this consumption is:

= 92kw(5.95 $/kw)

= $ 547.4

finally, the cost for the total consumption c is:

replace x in the equation and solve for y:

x = 1

y = 2(1) + 5 = 2 +5 = 7

(1,7)

x = 2

y = 2(2) +5 = 4+5=9

(2,9)

x = 3

y =2(3)+5 = 6+5 = 11

(3,11)

x = 4

y = 2(4)+5 = 8+5 = 13

(4,13)

ordered pairs:

(1,7) (2,9) (3,11) (4,13)