Arope, attached to a weight, goes up through a pulley at the ceiling and back down to a worker. the worker holds the rope at the same height as the connection point between the rope and weight. the distance from the connection point to the ceiling is 40 ft. suppose the worker stands directly next to the weight (i. e., a total rope length of 80 ft) and begins to walk away at a constant rate of 2 ft/s. how fast is the weight rising when the worker has walked: 10 feet? answer = 30 feet? answer =
5 multiplied by 1/3
you change 5 to 5/1 because it’s the same thing as 5 and multiply it by 1/3
5/1 x 1/3 and you get 5/3
choice a is correct answer.
y= mx+c is slope-intercept form for equation of line where m denotes slope and c denotes y-intercept.
slope is ratio of change in y to change in x.
slope= m = δy/δx
y-intercept is a point on graph where the value of x is zero.
given equation is :
y = 1/5x-6
hence,slope = m= 1/5 and y-intercept = c = -6
hence, choice a is your answer.
divide each term by 50, then simplify.(4x+12=4)
move all terms not containing x to the right side of the equation.(4x=-8)