what are the endpoint coordinates for the
midsegment of pqr that is parallel to
pq?
enter your answer, as a decimal or whole
number, in the boxes.

answer:

x = 7/12

step-by-step explanation:

to start, let's distribute the 3 across the 4x and -2 to get 3(4x) + 3(-2) = 1. now, we multiply to get 12x + (-6) = 1. next, we get 12x - 6 = 1. add 6 from both sides to get 12x = 7, and finally, if we divide both sides by 12, we get x = 7/12.

answer:

3/4·(2·x - 7) ≤ 5

3·(2·x - 7) ≤ 20

2·x - 7 ≤ 20/3

2·x ≤ 20/3 + 7

2·x ≤ 20/3 + 21/3

2·x ≤ 41/3

x ≤ 41/6

i can give you as many sums as you want!

all of these sums are 15, just so you know.

0 + 15 = 15

1 + 14 = 15

2 + 13 = 15

3 + 12 = 15

4 + 11 = 15

5 + 10 = 15

6 + 9 = 15

7 + 8 = 15

8 + 7 = 15

9 + 6 = 15

10 + 5 = 15

11 + 4 = 15

12 + 3 = 15

13 + 2 = 15

14 + 1 = 15

15 + 0 = 15

hope this !

plz mark brainliest!

answer:

x = 63.08 lbs ≈ 63 lbs

step-by-step explanation:

you will solve this problem in the same way, to make proportion:

26 : 41 = 40 : x

when we multiply external and internal members we get:

26 x = 40 · 41 = 1640 => 26 x = 1640 => x = 1640/26 = 63.076 ≈ 63 lbs

x = 63 lbs

god with !