given that a ball is thrown verically upwards with an initial velocity. we know that the path is a trajectory as a parabola.
from graph we find that horizontal is in yards and vertical is in feet.
we have to find the coordinates of a
when ball is thrown upward, acceleration due to gravity is -32 ft/s^2
since height = s=+h0
we get h0 as initial height.
but without any calculation from the graph we find out these coordinates as
x coordinate = 2.5(since in the middle of 0 and 5)
y coordinate = 10.5(since in the middle of 9 and 12)
(2.5,10.5) is the coordinate of a
answer:s = 66
s + 24 = 90 subtract 24 from both sides
s + 24 - 24 = 90 - 24
s = 66
19.75 / 5 * 9
all you gotta do is add.