50 large trucks, 90 small trucks, 180 vans
this problem can be solved by setting up a system of equations and using substitution to solve for a variable. given there are three types of vehicles, but that the number of vans is twice the number of small trucks, we can set up two variables:
large trucks = t, small trucks = s, commercial vans = 2s
the sum of all types of vehicles is 320: t + s + 2s = 320 or t + 3s = 320
the company can spend $13million and the cost of each vehicle is given:
80,000t + 50000s + 25000(2s) = 13,000,000
combine like terms: 80,000t + 100,000s = 13,000,000
use t = 320 - 3s to substitute for 't' in the second equation:
80,000(320 - 3s) + 100,000s = 13,000,000
25,600,000 - 240,000s + 100,000 = 13,000,000
-140,000s = -12,600,000 or s = 90
small trucks = 90, large trucks = 50 and commercial vans = 180
bill suffered a loss of 42.85%.
bill bought a home for $210000 and sold it for $120000 and we have to calculate the percentage loss he suffered.
as we know loss suffered = difference of sale price and cost price of the home.
total loss = 210000-120000 = $90000
now percentage loss =
= 9/21×100 = 3×100/7 = 42.85%
so the answer is 42.85% loss.
hello from mrbilldoesmath!
first glance at the numbers shows each term is 1 larger than the preceding terms. so we are adding the constant 1 to each term to get the next term. this is an arithmetic progression.