17. (a) will the electric field strength between two parallel conducting plates exceed the breakdown strength for air ( 3.0×106 v/m ) if the plates are separated by 2.00 mm and 5.0×103 v a potential difference of is applied? (b) how close together can the plates be with this applied voltage?
the statement is false.
only four examples are listed.
momentum = (mass) x (speed) .
so 907,175 kg-m/s = (36,287 kg) x (speed)
divide each side by (36,287 kg):
speed = (907,175 kg-m/s) / (36,287 kg)
speed = 25 m/s
that's the truck's speed. we can't do anything that involves the truck's velocity, because we don't know what direction the truck is moving.
answer; ///i believe that the correct answer is (carbon); ///// good luck