At the end of a rocket launch of a space vehicle from a launch site on the earth’s equator, the following burnout conditions hold. the burnout altitude is 110 km, and the burnout velocity vector lies in the equatorial plane with magnitude 8.3 km/s and flight path angle of 3 degrees above the local horizontal.
after burnout, the space vehicle moves along a two-body orbit.
(a) what is the specific angular momentum of the orbit of the space vehicle? what is the specific total energy of the orbit of the space vehicle?
(b) what is the orbital eccentricity?
what you are describing is a difference in the nucleus of neutrons.
elements: these chemicals are what is on the periodic table.
ions: these have either too many electrons or too few electrons from the elements found on the periodic table.
nuclei: are the part of the atom found at the center.
the three above are not the answer.
the answer is c
here is the answer calculate the area of the base (which is a circle) by using the equation πr² where r is the radius of the circle. then, multiply the area of the base by the height of the cylinder to find the volume.