The masses of the blocks are m1 = 16.0 kg and m2 = 12.0 kg, the mass of the pulley is m = 5.00 kg, and the radius of the pulley is r = 0.300 m. block m2 is initially on the floor, and block m1 is initially 4.60 m above the floor when it is released from rest. the pulley's axis has negligible friction. the mass of the string is small enough to be ignored, and the string does not slip on the pulley, nor does it stretch.
a. how much time (in s) does it take block m1 to hit the floor after being released?
b. how would your answer to part (a) change if the mass of the pulley were neglected? (enter the time, in seconds, it takes block m1 to hit the floor if the mass of the pulley were neglected.)
when ball will reach to highest point then it's speed will become zero
so we can use kinematics to find the time
for finding the maximum height we can use another kinematics equation
so it will rise to 1.12 m from the point of projection
ball will take double the time which it take to reach the top point.
so here the time to reach the top is 2.23 s
so time taken by the ball to reach at same point after projection is given as
since ball have reached to same point so the final velocity must be same as initial velocity
so we have
when ball reached to the bottom
displacement of ball = -51.6 m
now by kinematics we have
by solving above equation we have
now for the velocity at that instant we have
so its velocity is 38.6 m/s downwards
for the position of ball at t = 5.35 s we can use
so it is 23.1 m below the initial position from which it is thrown
now for the velocity we can say
so it will be moving downwards with speed 30.53 m/s
not too sure on this one maybe to locate objects under water, to diagnose problems, to treat medical ailments
the angle near the y-axis is 60°, beause 90°-30°=60°. vy=10m/s*sin60°=8.66m/s